q
[tex] \sf1). \: \: ( \frac{8}{ \frac{8}{2} } ) {x}^{2} + 2x - 30 = 0[/tex]
= ..............
[tex]( \frac{8}{ \frac{8}{2} } ) {x}^{2} + 2x - 30 = 0[/tex]
[tex]( \frac{8}{4} ) {x}^{2} + 2x - 30 = 0[/tex]
[tex]2 {x}^{2} + 2x - 30 = 0[/tex]
[tex] \frac{ - b \:\underline + \: \sqrt{ {b}^{2} - 4ac } }{2a} [/tex]
[tex] \frac{ - 2\:\underline + \: \sqrt{ {2}^{2} - 4 \times 2 \times ( - 30)} }{2 \times 2} [/tex]
[tex] \frac{ - 2\:\underline + \: \sqrt{4 - 8 \times ( - 30)} }{4} [/tex]
[tex] \frac{ - 2\:\underline + \: \sqrt{4 - ( - 240)} }{4} [/tex]
[tex] \frac{ - 2\:\underline + \: \sqrt{4 + 240} }{4} [/tex]
[tex] \frac{ - 2\:\underline + \: \sqrt{244} }{4} [/tex]
[tex] \frac{ - 2\:\underline + \: \sqrt{4 \times 61} }{4} [/tex]
[tex] \frac{ - 2\:\underline + \: 2 \sqrt{61} }{4} [/tex]
[tex] \frac{\cancel{ - 2}\:\underline + \:\cancel2 \sqrt{61} }{\cancel4} [/tex]
[tex] \frac{ - 1\:\underline + \: \sqrt{61} }{2} [/tex]
[tex]\boxed{\sf\blue{x_1 = \frac{ - 1 + \sqrt{61} }{2} }}[/tex]
[tex]\boxed{\sf\blue{x_2 = \frac{ - 1 - \sqrt{61} }{2} }}[/tex]
Jawaban:
untuk jalan dan jawabannya ada digambar ya kak
semoga membantu kak (:
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